Discussion:
roots to *any* polynomial
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Jon
2009-11-26 18:32:12 UTC
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http://jons-math.bravehost.com/rootformula.html

This solution for the roots of *any* polynomial requires some manipulation
of complex numbers. An example for the solutions to the Pentic is provided.
Dik T. Winter
2009-11-27 14:42:13 UTC
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Post by Jon
http://jons-math.bravehost.com/rootformula.html
This solution for the roots of *any* polynomial requires some manipulation
of complex numbers. An example for the solutions to the Pentic is provided.
Take for your quintic a = b = 1, c = -2. Your formula gives:

x = {{3^(1/5) - 2}^(1/4)

which not even close to the actual root of 1.
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dik t. winter, cwi, science park 123, 1098 xg amsterdam, nederland, +31205924131
home: bovenover 215, 1025 jn amsterdam, nederland; http://www.cwi.nl/~dik/
Heissenburger
2010-06-18 21:43:28 UTC
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check out this free website
http://www.wolframalpha.com/

it (tries to) solves everything!
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Post by Jon
http://jons-math.bravehost.com/rootformula.html
This solution for the roots of *any* polynomial requires some manipulation
of complex numbers. An example for the solutions to the Pentic is provided.
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